What are the dimensions of each pixel if an image is acquired into a 128 x 128 matrix on a scintillation camera with a 350mm diameter field of view?

Study for the Nuclear Medicine Exam. Study with flashcards and multiple choice questions, each question has hints and explanations. Get ready for your exam!

To determine the dimensions of each pixel in an image acquired on a scintillation camera with a specified matrix size and field of view, we can use the following formula:

Pixel Size = (Field of View Diameter) / (Matrix Dimension)

In this case, the field of view (FOV) diameter is 350 mm, and the matrix size is 128 x 128. This means that the image is composed of 128 pixels both horizontally and vertically.

First, we calculate the size of each pixel in millimeters:

  1. The pixel size can be calculated for one dimension (either width or height since it's a square matrix):

Pixel Size = 350 mm / 128 pixels

Now, performing the calculation:

Pixel Size = 350 mm / 128 ≈ 2.734375 mm

This value rounds to approximately 2.73 mm when considering typical significant figures in measurements.

As a result, since each pixel is square, the dimensions of each pixel are 2.73 mm x 2.73 mm. Thus, the correct answer, providing the pixel dimensions, would be the option identified.

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